 # matrices – Solution of complicated linear system Answer

Hello expensive customer to our community We will proffer you an answer to this query matrices – Solution of complicated linear system ,and the respond will breathe typical by means of documented data sources, We welcome you and proffer you fresh questions and solutions, Many customer are questioning in regards to the respond to this query.

matrices – Solution of complicated linear system

In Brubeck, Nakatsukasa, and Trefethen – Vandermonde with Arnoldi (instance 3) they decipher the next linear system:
$$operatorname{Re}left(commence{array}{ccc}1 & cdots & z_{1}^{n} 1 & cdots & z_{2}^{n} vdots & ddots & vdots 1 & cdots & z_{m}^{n}aim{array}privilege)left(commence{array}{c}a_{0} vdots a_{n}aim{array}privilege)-operatorname{Im}left(commence{array}{ccc}z_{1} & cdots & z_{1}^{n} z_{2} & cdots & z_{2}^{n} vdots & ddots & vdots z_{m} & cdots & z_{m}^{n}aim{array}privilege)left(commence{array}{c}b_{1} vdots b_{n}aim{array}privilege)approxleft(commence{array}{c}f_{1} f_{2} vdots f_{m}aim{array}privilege).$$

$$A=left(commence{array}{ccc}1 & cdots & z_{1}^{n} 1 & cdots & z_{2}^{n} vdots & ddots & vdots 1 & cdots & z_{m}^{n}aim{array}privilege)$$.

For fixing it, they employ the next MATLAB code:

``````c = [real(A) imag(A(:,2:n+1))]f;
c = c(1:n+1) - 1i*[0; c(n+2:2*n+1)];
``````

The first line is equal to making a vector `c=[a,b]` the place $$operatorname{Re}(A)aapprox f$$ and $$operatorname{Im}(A(:,2:n+1))b approx f$$ and the second means $$c=a-[0,bi]$$. I used to be questioning the way it can breathe solved on this route, in truth I reproduced the code of the paper in Mathematica and the outcomes are usually not the identical. Is there any typo on this process?

we are going to proffer you the answer to matrices – Solution of complicated linear system query through our community which brings all of the solutions from a number of dependable sources.